Description sangar 2011-08-20 22:28:01 EDT

Build Identifier: 20110615-0604

The parser seems to fail inferring the type of an explicitly specialized template of a function, when the type is used as the result type (does not happen when it's used for a parameter of the function).
It does work (not display the error) when explicitly specifying the type like so:

template< typename T >
T f();

template<>
int f<int>() { //< explicit <int> here makes it work
	return 0;
}


Reproducible: Always

Steps to Reproduce:
1. Create new empty C++ project.
2. Create new empty source file.
3. Insert the following code:

template< typename T >
T f();

template<>
int f() { //< Symbol 'f' could not be resolved
	return 0;
}