Comment 1 Darin Wright 2010-06-30 11:17:31 EDT

This works for me. Anything in your .log?

Comment 2 MH 2010-06-30 12:46:47 EDT

Hm, after I changed it to

  new java.util.Date(currentDateMillis)

it works again. I noticed the same behaviour in the display view: 

  return new Date(currentDateMillis);

doesn't work anymore but

   return new java.util.Date(currentDateMillis);


Why that? Why do we have to fully state the package with Helios as the former Eclipse didn't need that?

Comment 3 Darin Wright 2010-06-30 13:21:36 EDT

(In reply to comment #2)
> Why that? Why do we have to fully state the package with Helios as the former
> Eclipse didn't need that?

This should be no different in Helios - the expression is evaluated in the context of the current frame - if the frame has visiblity to Date, it works. If the frame does not have visiblity to Date, you need to fully qualify it.

I verified this by having a class that does not import date and one that does. In the later case using "new Date(...)" worked.

Comment 4 MH 2010-07-01 01:51:39 EDT

Well, it _did_ change in Helios as Ihave such in expressions in Eclipse for years and suddenly in Helios they don't work anymore. There has to be a change in Helios for this. The main projects I work and debug everyday with had not this problem before helios. The very same projects/Java sources/imports suddenly don't "work" for the expressions view ... think about it.

Comment 5 Darin Wright 2010-07-01 11:25:35 EDT

My test shows the same behavior in 3.5 and 3.6.

With the following class I can use the expression "new Date(longValue)"

import java.util.Date;

public class Main {
	public static void main(String[] args) {
		Date date = new Date();
		long longValue = System.currentTimeMillis();
		for (int i = 0; i < 100; i++) {
			longValue += (long) (i * 100000);
		}
	}
}



With the following class I have to use "new java.util.Date(longValue)"

public class Main {
	public static void main(String[] args) {
		long longValue = System.currentTimeMillis();
		for (int i = 0; i < 100; i++) {
			longValue += (long) (i * 100000);
		}
	}
}