Bug 367543

Description Max Schaefer 2011-12-25 08:57:03 EST

Build Identifier: M20110909-1335

Test case:

  public class A {
    int foo() {
      int r = 42; // extract this line
      return r;
    }

    public static void main(String[] args) {
      System.out.println(new B().foo());
    }
  }

  class B extends A {
    public int m() {
      return 23;
    }
  }

This program prints 42. Extracting the indicated line into a new method m yields the following program, which prints 23:

  public class A {
    int foo() {
      int r = m();
      return r;
    }

    public int m() {
      int r = 42;
      return r;
    }

    public static void main(String[] args) {
      System.out.println(new B().foo());
    }
  }

  class B extends A {
    public int m() {
      return 23;
    }
  }

The problem is that the extracted method is overridden in B, so the extracted call m() resolves to B.m instead of the extracted method A.m on objects of class B.

Reproducible: Always

Steps to Reproduce:
See above.