Bug 366549

Description Stephen DiMilla 2011-12-13 10:04:50 EST

Build Identifier: eclipselink-2.3.0.v20110604-r9504

Using the entity:
@Entity
@Table(name = "EMPLOYEE")
public class Employee implements java.io.Serializable, Comparable<Employee> {

    private int id;
    private String firstName;

    public Employee() {
    }

    public Employee(int id, String firstName) {
        this.id = id;
        this.firstName = firstName;
    }



    // ===========================================================
    // getters and setters for the state fields

    @Id
    @Column(name = "ID")
    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    @Column(name = "FIRSTNAME")
    public String getFirstName() {
        return firstName;
    }

----------------
Client Code:

       try {
            Query query = em.createQuery("select e from Employee e where e.firstName = ?1");
            query.getParameterValue(1);
            System.out.println("IllegalStateException not thrown");
        } catch (IllegalStateException e) {
            System.out.println("Received expected IllegalStateException");
        } catch (Exception e) {
            System.out.println("Unexpected exception occurred", e);
        }

---------------
Output:

Unexpected exception occurred
java.lang.IllegalArgumentException: No paramter with name : fname1 was found within the query: ReadAllQuery(referenceClass=Employee sql="SELECT ID, FIRSTNAME FROM EMPLOYEE WHERE (FIRSTNAME = ?)").
[javatest.batch] 	
	at org.eclipse.persistence.internal.jpa.EJBQueryImpl.getParameterValue(EJBQueryImpl.java:1437)

Reproducible: Always