Bugzilla – Full Text Bug Listing
| Summary: | Type Hierarchy fails for classes derived from a template class | ||
|---|---|---|---|
| Product: | [Tools] CDT | Reporter: | Tim <minesadab> |
| Component: | cdt-parser | Assignee: | Project Inbox <cdt-parser-inbox> |
| Status: | CLOSED DUPLICATE | QA Contact: | Markus Schorn <mschorn.eclipse> |
| Severity: | normal | ||
| Priority: | P3 | CC: | cdtdoug |
| Version: | 8.0 | ||
| Target Milestone: | --- | ||
| Hardware: | PC | ||
| OS: | Windows 7 | ||
| Whiteboard: | |||
*** This bug has been marked as a duplicate of bug 230925 *** |
Build Identifier: M20100909-0800 When I try to display the Type Hierarchy for class A that is derived from a template class, the supertypes of class A are not shown (ie the template class from which class A is derived does not appear in the hierarchy, and class A is in fact shown as the highest class) Reproducible: Always Steps to Reproduce: The following code can be used to reproduce. If an "Open Type Hierarchy" is performed on DerivedClassA, its base class (SuperType) is not shown in the hierarchy. template <class T> class SuperType { T testType; }; class DerivedClassA : public SuperType<int> { };